DU BOIS LEMMA

Science — acosta @ 8:28 am

I used something in my course on continuum mechanics last week that was pretty interesting, and I only now realize I’ve used it all the time without ever thinking about it. It is the so-called “Du Bois-Reymond Lemma”, and it goes something like: if an integral formula equals zero and is a continuous indefinite integral, then the integrand must vanish. It’s so ridiculously simple and yet I never actually thought about it before. This is particularly useful when, for instance, deriving the equation of continuity from the mass conservation form of the Reynold’s Transport Theorem.

\frac{d}{dt}\iiint_{V(t)}f(\mathbf{x},t)dV = \iiint_{V(t)} \left[\frac{\partial f}{\partial t} + \nabla\cdot\left(f\mathbf{v}\right)\right]dV

Apply to mass conservation by,

\iiint_{V(t)}\rho(\mathbf{x},t)dV = m
\frac{dm}{dt} = 0

And we have,

0 = \iiint_V \left[\frac{d\rho}{dt} + \rho\left(\nabla\cdot\mathbf{v}\right)\right]dV

Therefore the equation of continuity is simply,

\frac{\partial \rho}{\partial t} + \nabla\cdot(\rho\mathbf{v}) = 0

Fun. Cheers.

2 Comments »

  1. Ha! Nice to know the name of that little trick. Now I can sound smart when I’m talking to mantle dynamics people. Yay.

    Comment by chibi — 10/14/2007 @ 8:33 am
  2. 1) I’d call this the “fundamental theorem of calculus” applied to a homogeneous equation or a conversion from the variational (in functional analysis) or integral form to the differential form. But I never learned the named organic reactions either.

    2) This lemma is a good named lemma to know. It also appears in electromagnetism (to convert between the forms of Maxwell’s equations) and in classical mechanics (in the derivation of the Euler-Lagrange equations).

    3) The integral can be definite.

    4) What’s going on with your domain of integration? Is it really time-dependent?

    Comment by jrgreen — 11/12/2007 @ 1:18 pm

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